[Ron Ramirez]

Please read:
http://www.philcoradio.com/tech/resistor.htm

The original resistors in the 38-12 will follow the color coding as explained under "A Word about Color Codes" on the page linked above.

You see one stripe at one end of a resistor, and another stripe in the middle, with the rest of the resistor body a third color, yes?

So, let's take each of your resistors in sequence...

#1. Brown body, white stripe on end, yellow stripe in middle = 1 9 0000 = 190K
#2. Lavender (violet) body, black stripe on end, black stripe in middle = 7 0 .0 = 70 ohms
#3. Yellow body, black stripe on end, green stripe in middle = 4 0 00000 = 4 meg
#4. Brown body, black stripe on end, green stripe in middle = 1 0 00000 = 1 meg. If it were a 2 meg resistor, it would have a red body.
#5. Yellow body, black stripe on end, orange stripe in middle = 4 0 000 = 40K
#6. Green body, brown stripe on end, yellow stripe in middle = 5 1 0000 = 510K. So that "yellow" stripe is probably an orange stripe, which would make it 5 1 000 = 51K.
#7. Green body, brown stripe on end, orange stripe in middle = 5 1 000 = 51K.

See, it isn't that difficult once you get used to the fact that what appears to be a second stripe is actually part of the resistor body color.

And, your first, second, third and seventh resistors are within 20% tolerance. The others are outside the permissible 20% tolerance and must be replaced.

Edit: I see Codefox posted as I was typing. I agree with his comment.